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\(f^-1\)(x) = \( {x^2 +5{} \over 2}\frac{}{}\)

solve the equation f^-1(x) =7

 Aug 16, 2019
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\(\dfrac{x^2+5}{2} = 7\\ x^2 + 5 = 14\\ x^2 = 9\\ x = \pm 3\)

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 Aug 16, 2019

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