What is the greatest common divisor of $121^2 + 233^2 + 345^2$ and $120^2 + 232^2 + 346^2$?
The gcd is 1.
GCD((121^2 + 233^2 + 345^2), (120^2 + 232^2 + 346^2))
Prime factorizations 187955 = 5×37591 (2 distinct prime factors) 187940 = 2^2×5×9397 (4 prime factors, 3 distinct)
GCD == 5
