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What is the greatest common divisor of $121^2 + 233^2 + 345^2$ and $120^2 + 232^2 + 346^2$?

 Jul 11, 2022
 #1
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The gcd is 1.

 Jul 11, 2022
 #2
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GCD((121^2 + 233^2 + 345^2), (120^2 + 232^2 + 346^2))


Prime factorizations
187955 = 5×37591 (2 distinct prime factors)
187940 = 2^2×5×9397 (4 prime factors, 3 distinct)


GCD == 5

 Jul 11, 2022

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