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A triangle has vertices at coordinates (11,1), (2,3) and (3,7). What is the number of units in the length of the longest side of the triangle?

 Jul 6, 2019
 #1
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Distance between    (11,1)  and (2,3)  =  sqrt  [ (11-2)^2 + (3 - 1)^2 ]  = sqrt [ 9^2 + 2^2]  = sqrt [ 85]

 

Distance between (11,1) and (3,7)  = sqrt [ (11-3)^2 + (7 - 1)^2 ] = sqrt [ 8^2 + 6^2 ] = sqrt [64 + 36 ] =   sqrt [100]

 

Distance between (2.3) and (3,7)  = sqrt [ (3 -2)^2 + (7 - 3)^2 ] = sqrt [ 1^2 + 4^2]  = sqrt [ 17 ]

 

So..the longest side is sqrt (100)  = 10 units

 

 

 

 

cool cool cool

 Jul 6, 2019
 #2
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smiley Thank You saar

Guest Jul 7, 2019

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