A triangle has vertices at coordinates (11,1), (2,3) and (3,7). What is the number of units in the length of the longest side of the triangle?
+128407 Distance between (11,1) and (2,3) = sqrt [ (11-2)^2 + (3 - 1)^2 ] = sqrt [ 9^2 + 2^2] = sqrt [ 85]
Distance between (11,1) and (3,7) = sqrt [ (11-3)^2 + (7 - 1)^2 ] = sqrt [ 8^2 + 6^2 ] = sqrt [64 + 36 ] = sqrt [100]
Distance between (2.3) and (3,7) = sqrt [ (3 -2)^2 + (7 - 3)^2 ] = sqrt [ 1^2 + 4^2] = sqrt [ 17 ]
So..the longest side is sqrt (100) = 10 units
Thank You saar
