Find the minimum value of y = (2^x - 1)(2^x - 2).
Here is a graph:
0.5849625,−0.25) is a local minima, is this what you are looking for?:
x=ln(32+√1+4y2)ln(2)x=ln(32+1+4y2)ln(2)
x=ln(32−√1+4y2)ln(2)x=ln(32-1+4y2)ln(2)
EP, why did you delete your answer?
I initially read the Q incorrectly.....d'oh!
oh, lol
+773 
