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Find the minimum value of y = (2^x - 1)(2^x - 2).

 Jun 25, 2020
 #1
avatar+28021 
+1

Here is a graph:

 

 Jun 25, 2020
edited by ElectricPavlov  Jun 25, 2020
edited by ElectricPavlov  Jun 25, 2020
 #2
avatar+752 
-2

0.5849625,−0.25) is a local minima,  is this what you are looking for?:

x=ln(32+√1+4y2)ln(2)x=ln(32+1+4y2)ln(2)

x=ln(32−√1+4y2)ln(2)x=ln(32-1+4y2)ln(2)

 Jun 25, 2020
 #3
avatar+752 
-2

EP, why did you delete your answer?

 Jun 25, 2020
 #4
avatar+28021 
0

I initially read the Q incorrectly.....d'oh!  cheeky

ElectricPavlov  Jun 25, 2020
 #5
avatar+752 
-2

oh, lol

 Jun 25, 2020

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