Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
To the nearest tenth of a unit, the radius of the circumscribed circle
is __?__ cm and m∠OAC = __?__°.
+23246 Since AOB is a diameter, angle(C) is inscribed in a semicircle, making angle(C) a right angle.
Using the Pythagorean Theorem on triangle(ACB), AB = 13, so its radius is 6.5 cm.
Since there are 180o in triangle(ACB) and angle(ACB) = 90o and angle(ABC) = 45.2o, angle(OAC) = 44.8o.
