Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.

To the nearest tenth of a unit, the radius of the circumscribed circle

is __?__ cm and m∠OAC = __?__°.

Guest Apr 22, 2020

#1**+1 **

Since AOB is a diameter, angle(C) is inscribed in a semicircle, making angle(C) a right angle.

Using the Pythagorean Theorem on triangle(ACB), AB = 13, so its radius is 6.5 cm.

Since there are 180^{o} in triangle(ACB) and angle(ACB) = 90^{o} and angle(ABC) = 45.2^{o}, angle(OAC) = 44.8^{o}.

geno3141 Apr 22, 2020