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Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
To the nearest tenth of a unit, the radius of the circumscribed circle
is __?__ cm and m∠OAC = __?__°.

 

 Apr 22, 2020
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Since AOB is a diameter, angle(C) is inscribed in a semicircle, making angle(C) a right angle.

Using the Pythagorean Theorem on triangle(ACB), AB  =  13, so its radius is 6.5 cm.

 

Since there are 180o in triangle(ACB) and angle(ACB) = 90o and angle(ABC) = 45.2o, angle(OAC) = 44.8o.

 Apr 22, 2020

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