How many solutions does the system have?
y=−2x+4
y=x^2−2x+4
Set the y's equal and we have
x^2−2x+4 = -2x + 4 subtract 4 from each side
x^2 - 2x = - 2x add 2x to both sides
x^2 = 0
x = 0
One solution
(0, 4)
