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avatar+168 

How many solutions does the system have?

 

y=−2x+4

y=x^2−2x+4

 Feb 21, 2019
 #1
avatar+103140 
+2

Set the y's equal  and we have 

 

x^2−2x+4  = -2x + 4      subtract  4 from each side

 

x^2 - 2x = - 2x     add  2x to both sides

 

x^2 = 0

 

x = 0

 

One solution

 

(0, 4)

 

cool cool  cool

 Feb 21, 2019

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