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\(\angle ACD=\angle ABC =x\\ \angle BDC=\angle BCD=y \)

so:

2y+x=180°

x=180°-2y

x=180°-2y

48°+(180°-y)+x=180°

48°+(180°-y)+(180°-2y)=180°

-3y=(180-180-180-48)°

-3y=-228°

y=76°

x=180°-2*76°

x=28°

\(\angle ABC=28°\)

  !