3 years ago a father was 3 times as old as his son in 5 years time he will be twice as old as his son in, what will be the sum of their years in four years time
+36916 f -3 = 3 ( s -3)
f+5 = 2 (s+5)
f-3 = 3s-9 and
f+5 = 2s+10 or -f-5 = -2s-10 add this to the first equation
-8 = s -19
s = 11 f -3 = 3(s-3)
f = 3(11-3) + 3 = 27
11+4 + 27 + 4 = 46 years total in 4 years time
