+71 The angle of elevation from a viewer to the top of a flagpole is 50˚. The viewer is 40 ft away and the viewer’s eyes are 5.5 ft from the ground. How high is the pole to the nearest tenth of a foot?
+2094 Hint:
Tan 50 degrees will represent the angle of elevation. Now, write the equation.
Hope this helped!
+500 Tan 50 is not the angle of elevation, that's arctan of that ratio. Tangent is a ratio of sides, not the angle itself. The inverse sine (arcsin)is the angle itself given the sine for example. Consequently, the inverse tangent(arctan) is the angle itself given the tangent.
+36916 tan50 = opposite/adjacent opposite is height adjacent is 40 ft
= height / 40 when you figure out THIS height you must add the 5.5 ft observer's height
tan 50 = 1.191754
