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# Help?

+10
649
4

Factor x^2-8x-48

Nov 24, 2015

#3
+20

Hi Olivia,

Thanks guests,

I just want to discuss this a bit more  :))

Factor         \(x^2-8x-48\)

Like guest 2 said you need

2 numbers that multipy to -48 and add to -8

They multiply to a negative number so one must be negative and one must be positive.

Now they add to a negative SO the 'bigger' one is negative.

Mmm

So what multiplies to -48  where the 'bigger' one is negative.

possibilities are

1 and -48,

2,and -24,

3 and -16,

4 and -12,

6 and -8

which of these add to -8?     4 and -12  that the only one.

so

x^2-8x-48 = (x+4)(x-12) Nov 24, 2015

#2
+15

Factor the following:
x^2-8 x-48

The factors of -48 that sum to -8 are 4 and -12. So, x^2-8 x-48 = (x+4) (x-12):

Nov 24, 2015
#3
+20

Hi Olivia,

Thanks guests,

I just want to discuss this a bit more  :))

Factor         \(x^2-8x-48\)

Like guest 2 said you need

2 numbers that multipy to -48 and add to -8

They multiply to a negative number so one must be negative and one must be positive.

Now they add to a negative SO the 'bigger' one is negative.

Mmm

So what multiplies to -48  where the 'bigger' one is negative.

possibilities are

1 and -48,

2,and -24,

3 and -16,

4 and -12,

6 and -8

which of these add to -8?     4 and -12  that the only one.

so

x^2-8x-48 = (x+4)(x-12) Melody Nov 24, 2015
#4
+15

Thanks, you guys!!!!   Nov 24, 2015