#3**+20 **

Hi Olivia,

Thanks guests,

I just want to discuss this a bit more :))

Factor \(x^2-8x-48\)

Like guest 2 said you need

2 numbers that multipy to -48 and add to -8

Think about the multiply first.

They multiply to a negative number so one must be negative and one must be positive.

Now they add to a negative SO the 'bigger' one is negative.

Mmm

So what multiplies to -48 where the 'bigger' one is negative.

possibilities are

1 and -48,

2,and -24,

3 and -16,

4 and -12,

6 and -8

which of these add to -8? 4 and -12 that the only one.

so

x^2-8x-48 = (x+4)(x-12)

Melody Nov 24, 2015

#2**+15 **

Factor the following:

x^2-8 x-48

The factors of -48 that sum to -8 are 4 and -12. So, x^2-8 x-48 = (x+4) (x-12):

**Answer: (x+4) (x-12)**

Guest Nov 24, 2015

#3**+20 **

Best Answer

Hi Olivia,

Thanks guests,

I just want to discuss this a bit more :))

Factor \(x^2-8x-48\)

Like guest 2 said you need

2 numbers that multipy to -48 and add to -8

Think about the multiply first.

They multiply to a negative number so one must be negative and one must be positive.

Now they add to a negative SO the 'bigger' one is negative.

Mmm

So what multiplies to -48 where the 'bigger' one is negative.

possibilities are

1 and -48,

2,and -24,

3 and -16,

4 and -12,

6 and -8

which of these add to -8? 4 and -12 that the only one.

so

x^2-8x-48 = (x+4)(x-12)

Melody Nov 24, 2015