Verify that x minus the square root of 6 is a factor of x to the fourth minus 36. My teacher didn't explain how to do this. What would you do?
x^4 - 36 can be factored as a difference of squares
( x^2 - 6) (x^2 + 6) note that the first factor is also a difference of two squares
(x - √6 ) ( x + √6) (x ^2 + 6) ........and it's completely factored [ in real terms ]....!!!!
