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Determine the sum of all 24 distinct 4 digit numbers formed by 2 3 7 9

 Dec 23, 2019
 #1
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{2, 3, 7, 9} | {2, 3, 9, 7} | {2, 7, 3, 9} | {2, 7, 9, 3} | {2, 9, 3, 7} | {2, 9, 7, 3} | {3, 2, 7, 9} | {3, 2, 9, 7} | {3, 7, 2, 9} | {3, 7, 9, 2} | {3, 9, 2, 7} | {3, 9, 7, 2} | {7, 2, 3, 9} | {7, 2, 9, 3} | {7, 3, 2, 9} | {7, 3, 9, 2} | {7, 9, 2, 3} | {7, 9, 3, 2} | {9, 2, 3, 7} | {9, 2, 7, 3} | ... (total: 24)

Ignore the commas between each pemutation and sum them up on a calculator like this:

2973 + 3279 + 3297......etc.

 Dec 23, 2019
 #2
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I have a question about this. Guest's way will definitely work, but is there some kind of easier way?

Thanks!

laugh

 Dec 23, 2019

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