Let \[f(x) = \begin{cases} x^2+9 &\text{if }x<-5, \\ 3x-8&\text{if }x\ge-5. \end{cases} \]If $f(x)=10$, find the sum of all possible values of $x$.
+128460 \( \[f(x) = \begin{cases} x^2+9 &\text{if }x<-5, \\ 3x-8&\text{if }x\ge-5. \end{cases} \]If $f(x)=10$\)
Find the sum of all possible values of x
If x^2 + 9 = 10
Then x^2 = 1
And x = ± 1 ..... but for this function, x < -5, so neither of these are good
If 3x - 8 = 10
3x = 18
x = 6 ....... and x ≥ -5
So....the sum of all possible values of x = 6
