Write the equation of a line PERPENDICULAR to y = -2x + 1 that passes through the point
(2, 3).
\(y=mx+c\) the perpendicular equation is:
\(y=-\frac{1}{m}x+c\) However, if it passes through another point then you need to find that point using the point-slope form:
\(y-y_1=m(x-x_1)\) (Since it is perpendicular then m will be \(-\frac{1}{m}\) (reciprocal opposite)(I.e. you flip the number or fraction and change sign)
\(y-3=\frac{1}{2}(x-2)\) Rearrange (solve for y)
\(y=\frac{1}{2}x+2\)
