If x is an integer, what is the smallest value of the expression x^2 - 6x +13?
x^2 - 6x + 13
The x value that minimizes this is given by - (-6) / [ 2 * 1 ] = 6 / 2 = 3
Subbing this back into the function, we have
(3)^2 - 6(3) + 13
9 - 18 + 13
22 - 18 =
4 = the minimum value for the expression
+80 
