+128406 1. We are just multiplying the terms under the radical
4√ 110
2.
3 √ [ 24a^10 b^6 ] =
3 √ [ 2^3 * 3 * a^10 * b^6 ] =
To determine how many powers of 2 to take out ⇒ 3/3 = 1
To determine how many powers of a to take out and leave in ⇒
10/3 = 3 + 1/3 ......3 powers come out and 1 stays in
To determine how many powers of b to take out ⇒
6/3 = 2 .....2 powers come out
2 * a^3 b^2 3 √ [ 3a ]
