#1**+2 **

1. We are just multiplying the terms under the radical

^{4}√ 110

2.

^{3} √ [ 24a^10 b^6 ] =

^{3} √ [ 2^3 * 3 * a^10 * b^6 ] =

To determine how many powers of 2 to take out ⇒ 3/3 = 1

To determine how many powers of a to take out and leave in ⇒

10/3 = 3 + 1/3 ......3 powers come out and 1 stays in

To determine how many powers of b to take out ⇒

6/3 = 2 .....2 powers come out

2 * a^3 b^2^{ } ^{3} √ [ 3a ]

CPhill
Jan 29, 2018