+0  
 
0
40
1
avatar+1690 

Help.

NotSoSmart  Jan 29, 2018
Sort: 

1+0 Answers

 #1
avatar+82687 
+2

1.   We are just multiplying the terms under the radical

 

4√ 110   

 

 

2.

 

3 √ [ 24a^10 b^6 ]   =

 

3 √  [  2^3  * 3  *  a^10 * b^6 ]   =

 

To determine how many  powers  of 2 to take out   ⇒  3/3  =  1

 

To determine how many powers of a to take out and leave in ⇒

10/3   =  3 + 1/3  ......3 powers come out and 1 stays in

 

To determine how many powers of b to take out  ⇒

6/3  =  2   .....2 powers come out 

 

2 * a^3 b^2    3 √ [ 3a ]

 

 

cool cool cool

CPhill  Jan 29, 2018

29 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details