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89
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avatar+2509 

Help.

NotSoSmart  Jan 29, 2018
 #1
avatar+86915 
+2

1.   We are just multiplying the terms under the radical

 

4√ 110   

 

 

2.

 

3 √ [ 24a^10 b^6 ]   =

 

3 √  [  2^3  * 3  *  a^10 * b^6 ]   =

 

To determine how many  powers  of 2 to take out   ⇒  3/3  =  1

 

To determine how many powers of a to take out and leave in ⇒

10/3   =  3 + 1/3  ......3 powers come out and 1 stays in

 

To determine how many powers of b to take out  ⇒

6/3  =  2   .....2 powers come out 

 

2 * a^3 b^2    3 √ [ 3a ]

 

 

cool cool cool

CPhill  Jan 29, 2018

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