The area of a rectangle is 28 ft^2, and the length of the rectangle is 1 ft more than twice the width. Find the dimensions of the rectangle.
+37144 Area of rectangle = L * W
Given : L = 2W +1
Substitute
2W+1 * W = 28 ft^2
2W^2 +W - 28 = 0
Use Quadratic Formul to find W = 14/4 or -4 (toss out the -4)
L = 2W + 1 = 2(14/4) + 1 = 8
L * W = 8 * 14/4 = 28
Area =2 x [L + W]
Width =W
Length =2W + 1
28 = 2 x [W + 2W + 1]
28 = 2 x [3W + 1]
28 = 6W + 2 Subtract 2 from both sides
26 = 6W Divide both sides by 6
W = 26 / 6 = 4 1/3 - feet - the width of the rectangle
[2 * 4 1/3] + 1 = 9 2/3 - feet - the length of the rectangle.
+37144 Area of rectangle = L * W
Given : L = 2W +1
Substitute
2W+1 * W = 28 ft^2
2W^2 +W - 28 = 0
Use Quadratic Formul to find W = 14/4 or -4 (toss out the -4)
L = 2W + 1 = 2(14/4) + 1 = 8
L * W = 8 * 14/4 = 28
