A TV antenna is on top of a tall building. A surveyor standing 53.5 m away measured the angle of elevation to the top of the building as 64o. She then measured the angle of elevation to the top of the antenna as 71o. What is the height of the TV antenna to the nearest tenth of a metre?
Looking for the hypotenuse of each right triangle given one leg (53.5 m) and one angle (64 or 71)
tan 63 = heightb /53.5 solve for height of building
tan 71 = heighta /53.5 solve for height of antenna antenna height is the difference between these two.....