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Solve for a: \(\frac15|9+2a|<1.\) Express your answer in interval notation.

 Jul 19, 2020
 #1
avatar+36915 
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|9+2a| < 5

 

must evaluate     9+ 2a < 5         a<-2

  and                    9+2a > -5         a> -7                    Interval for a :     (-7,-2)

 Jul 19, 2020
 #2
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Thank you so much!!!

AnimalMaster  Jul 19, 2020

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