*Madison went to the grocery store and purchased cans of soup and frozen dinners. Each can of soup has 500 mg of sodium and each frozen dinner has 700 mg of sodium. Madison purchased 2 more frozen dinners than cans of soup and they all collectively contain 7400 mg of sodium. Determine the number of cans of soup purchased and the number of frozen dinners purchased.*

Guest Mar 1, 2021

#1**+2 **

Let s mean the can of soup and d mean the frozen dinner.

If Madison purchased 2 more frozen dinners than cans of soup, then we have the equation \(d = s + 2\)

If each can of soup has 500 mg , each dinner is 700 mg, and that she bought 7400 mg of sodium total, we can come up with the equation \(500s + 700d = 7400\)

Replacing the d in \(500s + 700d = 7400\) with s + 2, we get the equation \(500s+700(s+2) = 7400\)

Using the distributive formula, we get

\(500s+700s+1400=7400\)

Simplifying this equation gives \(1200s = 6000\)

6000/1200 = 5

so s = 5

if d = s + 2, d must equal 7

So __Madison ordered 5 cans of soup and 7 frozen dinners.__

Correct me if im wrong

swag123456 Mar 1, 2021

#1**+2 **

Best Answer

Let s mean the can of soup and d mean the frozen dinner.

If Madison purchased 2 more frozen dinners than cans of soup, then we have the equation \(d = s + 2\)

If each can of soup has 500 mg , each dinner is 700 mg, and that she bought 7400 mg of sodium total, we can come up with the equation \(500s + 700d = 7400\)

Replacing the d in \(500s + 700d = 7400\) with s + 2, we get the equation \(500s+700(s+2) = 7400\)

Using the distributive formula, we get

\(500s+700s+1400=7400\)

Simplifying this equation gives \(1200s = 6000\)

6000/1200 = 5

so s = 5

if d = s + 2, d must equal 7

So __Madison ordered 5 cans of soup and 7 frozen dinners.__

Correct me if im wrong

swag123456 Mar 1, 2021