The real number x satisfies x^2-5x+6<0. Find all possible values of x^2+5x+6

Guest Nov 20, 2019

#1**+1 **

The solutoin so x^2 - 5x - 6 < 0 is -1 < x < 6, so the set of all possible values of x^2 + 5x + 6 is (2,72).

Guest Nov 20, 2019

#2**0 **

Guest made a teeny tiny mistake.

The answer is actually

\(2

EDIT: What happened to the LaTeX???????

CalculatorUser
Nov 20, 2019