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If \(x+y=\frac{7}{13} (and )x-y=\frac{1}{91},\) what is the value of \(x^2-y^2\)? Express your answer as a common fraction.

 Mar 19, 2020
 #1
avatar+111360 
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x + y   = 7/13

x - y   =  1/91

 

Note that   x^2 - y^2  can be factored as  ( x + y) (x - y)  .....substituting....we have  that

 

x^2 - y^2  =  ( 7/13) ( 1/91)   =   (7/91) (1/13)  =  (1/13)(1/13)  =  1 / 169

 

 

cool cool cool

 Mar 19, 2020

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