if slope of QR is x-1/4 and slope of ST is 8/3. If QR is perpendicular to ST what is the value of x
+129849 If the slope of QR = x - 1/4 ....a line perpendicular to it will have a negative reciprocal slope....=
-1 / [ x - 1/4]
And since ST is perpendicular.....it's slope 8/3 must = -1 / [x - 1/4]......cross-multiply and we have....
8 [x - 1/4] = 3 * -1
8x - 2 = -3 add 2 to both sides
8x = -1 divide both sides by 8
x = -1/8
