+140 Find the only value of x that satisfies:
\(\sqrt{7+\sqrt{4-\sqrt{3+x}}}=3\)
+738 \(\sqrt{7+\sqrt{4-\sqrt{3+x}}}=3\)
\(7+\sqrt{4-\sqrt{3+x}}=9\) (squared both sides)
\(\sqrt{4-\sqrt{3+x}}=2\) (subtracted 7 from both sides)
\(4-\sqrt{3+x}=4\) (square both sides again)
\(-\sqrt{3+x}=0\) (subtracted 4 from both sides)
\(\sqrt{3+x}=0\) (divided both sides by -1)
\(3+x=0\) (squared both sides again)
\(\boxed{x=-3}\)
