At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path The bicyclists headed north is riding 5 km/hour faster than the bicyclists headed south. At 10:45, they are 47.25 km apart find the two bicyclists' rates
+37099 Time involved = 900 to 1045 = 1.75 hr
x= speed of slower cyclist
1.75 hr * x = distance of slower cyclist
x+5 = faster cyclist's speed
1.75 hr *(x+5) = distance of faster cyclist
the two distances added together = 47.25
1.75 x + 1.75(x+5) = 47.25
3.5x + 8.75 = 47.25
3.5x = 38.5
x=11 km/hr = slower cyclist
x=5=16 km/hr = faster cyclist
