helppp

320

Let r and s be the roots of 3x^2+4x-12=0. Find r^2 + s^2

Guest Feb 27, 2022

+37153

By Vieta r + s = - 4/3 and r s = -12/3 = - 4

(r +s)^2 = r^2 + s^2 + 2 rs

(-4/3)^2 = ( r^2 + s^2) + 2 ( -4) you can finish, yah?

I still dont know, sorry i just don't

Guest Feb 28, 2022

+37153

(-4/3)^2 = ( r^2 + s^2) + 2 ( -4) you can finish, yah?

Just simple algebra from here :

16/9 = ( r² + s²) - 8

(16/9 ) + 8 = r² + s²