+73 Wilma and Greg were trying to solve the quadratic equation \(x^2 + bx + c = 0\). Wilma wrote down the wrong value of b (but her value of c was correct), and found the roots to be 1 and 6. Greg wrote down the wrong value of c (but his value of b was correct), and found the roots to be -1 and -4 What are the actual roots of \(x^2 + bx + c = 0\)?
+37146 Wilma (x-1)(x-6) = x^2 -7x + 6 but the '-7' is wrong and the 6 is correct
Greg (x+1)(x+4) = x^2 + 5x + 5 but the c = 5 is wrong
SO the equati0n must be x^2 + 5x + 6 which factors to (x+3)(x+2) roots -3 and -2
