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Wilma and Greg were trying to solve the quadratic equation \(x^2 + bx + c = 0\). Wilma wrote down the wrong value of b (but her value of c was correct), and found the roots to be 1 and 6. Greg wrote down the wrong value of c (but his value of b was correct), and found the roots to be -1 and -4 What are the actual roots of \(x^2 + bx + c = 0\)?

 Apr 20, 2020
 #1
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Wilma    (x-1)(x-6)  =   x^2 -7x +      but the '-7' is wrong and the 6 is correct

 

Greg      (x+1)(x+4) = x^2 + 5x + 5       but the c = 5 is wrong

 

 

SO the equati0n must be    x^2 + 5x + 6       which factors to   (x+3)(x+2)      roots   -3  and  -2

 Apr 20, 2020

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