Lines $y=(3a+2)x-2$ and $2y=(a-4)x+2$ are parallel. What is the value of $a$?
Put both lines into y = mx + b form m is the slope....for the lines to be || the slope must be the same
y = (3a+2)x - 2
y = 1/2(a-4) x +1 so 3a+ 2 = 1/2 (a-4) I'll let you finish......