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Lines $y=(3a+2)x-2$ and $2y=(a-4)x+2$ are parallel. What is the value of $a$?

 Jul 30, 2020
 #1
avatar+26735 
+1

Put both lines into   y = mx + b form     m is the slope....for the lines to be || the slope must be the same

 

y = (3a+2)x - 2

y = 1/2(a-4) x +1              so    3a+ 2   =  1/2 (a-4)     I'll let you finish......cheeky

 Jul 30, 2020
 #2
avatar+130 
+1

so ..... the answer would be 2 3/4 please correct me if im wrong

 Jul 30, 2020
 #3
avatar+1130 
+1

(1.)we make a graph 

 

https://www.geogebra.org/calculator/tpgvduhz

 

and we find that a=-1.6 to make lines \(y=(3a+2)x-2\) and \(2y=(a-4)x+2\) 

 

 

(2.)We can use slopes to find that 

 Jul 30, 2020
 #4
avatar+130 
+1

ohh ok

Creampuff  Jul 30, 2020
 #5
avatar+1130 
0

Your welcome

jimkey17  Jul 30, 2020

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