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# HELPPPP

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The sequence $$(a_n)$$ is defined by $$a_1=a_2=1$$and

$$a_{n + 2} = \begin{cases} a_n + a_{n + 1} \ \text{if n is even,} \\ a_n - a_{n + 1} \ \text{if n is odd.} \end{cases}$$

Compute $$a_1+a_2+a_3+\cdots+a_{100}$$.

Dec 20, 2021

#1
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$a_1 + a_2 + a_3 + \dots + a_{100} = \boxed{5}$

Dec 20, 2021
#2
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How did you get that?

Guest Dec 20, 2021
#3
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I wrote a computer program, so I'm sure the answer is right.

Guest Dec 20, 2021