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Let r and s be the roots of 3x^2 + 4x - 12 = 0. Find r^2 + s^2.

 Aug 14, 2022
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Use Vieta's Formulas:

\(r^2+s^2=(r+s)^2-2rs=(-\frac{4}{3})^2+8=\boxed{\frac{88}{9}}\)

 Aug 15, 2022

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