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The quadratic \(x^2-6x+66\) can be written in the form \((x+b)^2+c\), where \(b\) and \(c\) are constants. What is \(b+c\)?

somebody  Oct 16, 2018

Best Answer 

 #1
avatar+2742 
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\(x^2 - 6x + 66 = \\ x^2 - 6x + 9 - 9 + 66 = \\ (x-3)^2 + 57 \\ b=-3,~c=57\)

Rom  Oct 16, 2018
 #1
avatar+2742 
+2
Best Answer

\(x^2 - 6x + 66 = \\ x^2 - 6x + 9 - 9 + 66 = \\ (x-3)^2 + 57 \\ b=-3,~c=57\)

Rom  Oct 16, 2018

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