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A triangular region is enclosed by the lines with equations $y = \frac{1}{2} x + 3$, $y = -2x + 6$ and $y = 1$. What is the area of the triangular region? Express your answer as a decimal to the nearest hundredth.

 Oct 11, 2019

Best Answer 

 #3
avatar+19950 
0

The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

 

6.5 x 2.6 x 1/2 = 8.45  units2

 Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019
 #1
avatar+106539 
+1

y = (1/2)x  + 3

y = -2x + 6

y = 1

 

See the graph, here : https://www.desmos.com/calculator/6vqbm9hnpq

 

The vertex points of the triangular region  are   ( -4, 1)   (2.5, 1)  and  (1.2, 3.6)

 

The base of the triangular region has a length of  ( 2.5 - - 4)  = 6.5

 

The height of the triangular region is  ( 3.6 - 1)  = 2.6

 

So.....the area of the region is

 

(1/2) ( 6.5) ( 2.6)   =  8.45  units^2

 

CORRECTED ANSWER

 

 

cool cool cool

 Oct 11, 2019
edited by CPhill  Oct 11, 2019
edited by CPhill  Oct 11, 2019
 #2
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0

Nope but the answer was 8.45???

Guest Oct 11, 2019
 #3
avatar+19950 
0
Best Answer

The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

 

6.5 x 2.6 x 1/2 = 8.45  units2

ElectricPavlov Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019
 #4
avatar+106539 
0

Thanks for the correction, EP!!!!

 

 

cool cool cool

CPhill  Oct 11, 2019

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