We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
66
4
avatar

A triangular region is enclosed by the lines with equations $y = \frac{1}{2} x + 3$, $y = -2x + 6$ and $y = 1$. What is the area of the triangular region? Express your answer as a decimal to the nearest hundredth.

 Oct 11, 2019

Best Answer 

 #3
avatar+19797 
+1

The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

 

6.5 x 2.6 x 1/2 = 8.45  units2

 Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019
 #1
avatar+104782 
+1

y = (1/2)x  + 3

y = -2x + 6

y = 1

 

See the graph, here : https://www.desmos.com/calculator/6vqbm9hnpq

 

The vertex points of the triangular region  are   ( -4, 1)   (2.5, 1)  and  (1.2, 3.6)

 

The base of the triangular region has a length of  ( 2.5 - - 4)  = 6.5

 

The height of the triangular region is  ( 3.6 - 1)  = 2.6

 

So.....the area of the region is

 

(1/2) ( 6.5) ( 2.6)   =  8.45  units^2

 

CORRECTED ANSWER

 

 

cool cool cool

 Oct 11, 2019
edited by CPhill  Oct 11, 2019
edited by CPhill  Oct 11, 2019
 #2
avatar
0

Nope but the answer was 8.45???

Guest Oct 11, 2019
 #3
avatar+19797 
+1
Best Answer

The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

 

6.5 x 2.6 x 1/2 = 8.45  units2

ElectricPavlov Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019
 #4
avatar+104782 
0

Thanks for the correction, EP!!!!

 

 

cool cool cool

CPhill  Oct 11, 2019

23 Online Users