A triangular region is enclosed by the lines with equations $y = \frac{1}{2} x + 3$, $y = -2x + 6$ and $y = 1$. What is the area of the triangular region? Express your answer as a decimal to the nearest hundredth.

Guest Oct 11, 2019

#3**0 **

The graph shows it correctly BUT the base is 6.5 (not 6.25)....did YOU even look at the graph provided and understand the solution???

6.5 x 2.6 x 1/2 = 8.45 units^{2}

ElectricPavlov Oct 11, 2019

#1**+1 **

y = (1/2)x + 3

y = -2x + 6

y = 1

See the graph, here : https://www.desmos.com/calculator/6vqbm9hnpq

The vertex points of the triangular region are ( -4, 1) (2.5, 1) and (1.2, 3.6)

The base of the triangular region has a length of ( 2.5 - - 4) = 6.5

The height of the triangular region is ( 3.6 - 1) = 2.6

So.....the area of the region is

(1/2) ( 6.5) ( 2.6) = 8.45 units^2

CORRECTED ANSWER

CPhill Oct 11, 2019

#3**0 **

Best Answer

The graph shows it correctly BUT the base is 6.5 (not 6.25)....did YOU even look at the graph provided and understand the solution???

6.5 x 2.6 x 1/2 = 8.45 units^{2}

ElectricPavlov Oct 11, 2019