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# Helppppp

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A triangular region is enclosed by the lines with equations $y = \frac{1}{2} x + 3$, $y = -2x + 6$ and $y = 1$. What is the area of the triangular region? Express your answer as a decimal to the nearest hundredth.

Oct 11, 2019

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The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

6.5 x 2.6 x 1/2 = 8.45  units2

Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019

#1
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y = (1/2)x  + 3

y = -2x + 6

y = 1

See the graph, here : https://www.desmos.com/calculator/6vqbm9hnpq

The vertex points of the triangular region  are   ( -4, 1)   (2.5, 1)  and  (1.2, 3.6)

The base of the triangular region has a length of  ( 2.5 - - 4)  = 6.5

The height of the triangular region is  ( 3.6 - 1)  = 2.6

So.....the area of the region is

(1/2) ( 6.5) ( 2.6)   =  8.45  units^2   Oct 11, 2019
edited by CPhill  Oct 11, 2019
edited by CPhill  Oct 11, 2019
#2
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Nope but the answer was 8.45???

Guest Oct 11, 2019
#3
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The graph shows it correctly BUT the base is 6.5  (not 6.25)....did YOU even look at the graph provided and understand the solution???

6.5 x 2.6 x 1/2 = 8.45  units2

ElectricPavlov Oct 11, 2019
edited by ElectricPavlov  Oct 11, 2019
#4
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Thanks for the correction, EP!!!!   CPhill  Oct 11, 2019