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By partial fractions,
for some constants  \(By partial fractions, \[\frac{1}{x(x + 1)(x + 2)(x + 3)(x + 4)} = \frac{A}{x} + \frac{B}{x + 1} + \frac{C}{x + 2} + \frac{D}{x + 3} + \frac{E}{x + 4}\]for some constants $A,$ $B,$ $C,$ $D,$ and $E.$ Find $A + B + C + D + E.$\)  Find A+B+C+D+E

 Dec 8, 2020
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A + B + C + D + E = -1 + 2 + 4 + 2 + -1 = 6.

 Dec 8, 2020

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