If the point (1,-4) lies on the graph of f(x), then what would be a point on f^-1(x) ^-1 means the the power of -1
f(1) = -4
f-1(-4) = 1
So
[f-1 (-4)]-1 = [1]-1 = 1 so the point is (-4, 1 )
excuse me, so the new point is (-4,1), but how did you get the -4...... since you only get that 1 so confused
If (1, -4) is on f(x)......then ( -4, 1) is on f-1 (x)
So.....
f-1 (-4) = 1
[ f-1(-4)]-1 = [ 1 ]-1 = 1
So ( -4,1) is also on [ f-1(x)]-1
thank you, you save me a big time. Bless you
