If the point (1,-4) lies on the graph of f(x), then what would be a point on f^-1(x) ^-1 means the the power of -1

f(1) = -4

f^{-1}(-4) = 1

So

[f^{-1} (-4)]^{-1} = [1]^{-1} = 1 so the point is (-4, 1 )

excuse me, so the new point is (-4,1), but how did you get the -4...... since you only get that 1 so confused

If (1, -4) is on f(x)......then ( -4, 1) is on f^{-1} (x)

So.....

f^{-1} (-4) = 1

[ f^{-1}(-4)]^{-1} = [ 1 ]^{-1} = 1

So ( -4,1) is also on [ f^{-1}(x)]^{-1}

thank you, you save me a big time. Bless you