which of the following points is an equal distance (equidistant) from A(0,-4) and B(-2,0)?
A. J(-4,-5)
B. K(-3,0)
C. M(0,0)
D. N(3,0)
+130466 Let's first see what we can eliminate
(0, 0) isn't equidistant because it's 4 units from A and 2 units from B
(-3,0) is only 1 unit from B......it's 5 units from A
(-4, - 5)
√ [ (-4 - 0)^2 + (-5 +4)^2 = √ [16 + 1] = √ 17 from A
√ [(-4 +2)^2 + (-5 - 0)^2] = √ [ 4 + 25] = √29 from B
Then ( 3, 0) must be correct...proof :
√ [ (3 -0)^2 + (-4 -0)^2 ] = [ 9 + 16] = √25 = 5 units from A
√[ (-2 - 3)^2 + (0 - 0)^2 ] = √ (-5)^2 = √25 = 5 units from B
