An architect needs two support beams for a building. One beam has a length of 3÷3×2. The other one has a length of 3×2÷2. Explain how u can find which beam is longer?
If you use the usual rules of operations, multiplications and divisions and calculated, in order, from left to right.
3 / 3 x 2 = (3 / 3) x 2 = 1 x 2 = 2
3 x 2 / 2 = (3 x 2) / 2 = 6 / 2 = 3
