how do you solve 1/3(8)=(2x+1)(3x+1)
(1/3 )(8)=(2x+1)(3x+1)
(8/3) = 6x^2 + 5x + 1 mutiply through by 3
8 = 18x^2 + 15x + 3 subtract 8 from both sides
18x^2 + 15x - 5 = 0
Using the Quadratic formula, the two solutions are
x = [ - 5 ±√ 65 ] / 12
