find tan A if b= 8, c= 2sqrt17
\(tan=\frac{opos.}{adj.}\)
so let s use pithagorean theorem:
a^2+b^2=c^2
a^2+64=68
a=2
oposite of angle A is a
oposite of angle B is b
oposite of angle C is c (hyp.)
\(tan=\frac{opos.}{adj.}=\frac28\)
a = √ [ (2√17)^2 - 8^2] = √ [68 - 64 ] = √4 = 2
So
tan A = a / b = 2 / 8 = 1 / 4
tan-1 (1/4) = about 14.04°
