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if $\sqrt{2\sqrt{t-2}} = \sqrt[4]{7 - t}$ then find t.

 May 18, 2021
 #1
avatar+121056 
+2

We  have, in exponential  form  :

 

2^(1/2) (t  - 2)^(1/4)   =  (7 - t)^(1/4)       take  each  side to the  4th power

 

2^2 ( t - 2)  =  7- t

 

4  ( t - 2)  =  (7 - t)

 

4t  -  8  =  7  - t                   rearrange  as

 

5t  =  15

 

t  = 3

 

 

cool cool cool

 May 18, 2021
 #2
avatar+2205 
0

Start by squaring both sides. 

2sqrt(t-2) = sqrt(7-t)

sqrt(4t-8) = sqrt(7-t)

4t - 8 = 7 - t

5t = 15

t = 3

 

=^._.^=

 May 18, 2021

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