Suppose P, Q, and R are points in the plane such that PQ = 1.8, PR = 8.2 and angle PQR = 90 degrees. What is the area of angle PQR?
Angles don't have "areas "
The area of the triangle is PQ * QR / 2 = [1.8 * 8 ] / 2 = 7.2 units^2
now that you know the other side is 8 simply do 8 * 1.8 = 14.4
but remember since its a triangle you have to halve it which is 7.2