Suppose P, Q, and R are points in the plane such that PQ = 1.8, PR = 8.2 and angle PQR = 90 degrees. What is the area of angle PQR?

Angles don't have "areas "

The area of the triangle is PQ * QR / 2 = [1.8 * 8 ] / 2 = 7.2 units^2

now that you know the other side is 8 simply do 8 * 1.8 = 14.4

but remember since its a triangle you have to halve it which is 7.2

Thanks, YE.......T !!!!!!

I guess i didn't have to help when you're here

Thanks guys. I was wooried no one was going to answer me.