In triangle ABC, AB = BC = 17 and $AC = 16. Find the in radius of triangle ABC.
Acute isosceles triangle.
Sides: a = 17 b = 17 c = 16
Area: T = 120
Perimeter: p = 50
Semiperimeter: s = 25
Inradius
An incircle of a triangle is a circle which is tangent to each side. An incircle center is called incenter and has a radius named inradius. All triangles have an incenter, and it always lies inside the triangle. The incenter is the intersection of the three angle bisectors. The product of the inradius and semiperimeter (half the perimeter) of a triangle is its area.
Area =semiperimeter * inradius
Inradius =Area / semiprimeter
= 120 / 25
= 4.8 - the inradius of the triangle.
