If $a$ is the $x$-intercept, $b$ is the $y$-intercept, and $m$ is the slope of the line with equation $\frac{x}4 + \frac{y}{12} = 1$, then what is the value of $a + b + m$?
Multiplying the original equation through by 12 we get
3x + y = 12 rearrange as
y = -3x + 12
m = -3 b =12
x intercept....set y= 0
0 = -3x + 12
-12 = -3x
-12/-3 = 4 = x intercept = a
a + b + m =
4 + 12 - 3 =
13
Thanks!
OK.....
+14 
