\(WY\) is simply double of \(AY\), so that's \(2 \cdot 14 = 28\) :D
We know that the sum of the angles in a quadrilateral (like a rhombus) is \(360^{\circ}\), and opposite angles are equivalent.
So, \(m\angle WXY = m\angle WZY\), and \(m\angle ZWX = m\angle ZYX\).
We can use the pythagorean theorem to find \(XY\), because we know that \(XA = \frac{22}{2} = 11\) and \(AY = 14\). That will also be the length of \(WZ\).
So, what will the measures of the angles be? :D