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Quadrilateral WXYZ is a rhombus.

 

 May 3, 2020
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\(WY\) is simply double of \(AY\), so that's \(2 \cdot 14 = 28\) :D

 

We know that the sum of the angles in a quadrilateral (like a rhombus) is \(360^{\circ}\), and opposite angles are equivalent.

 

So, \(m\angle WXY = m\angle WZY\), and \(m\angle ZWX = m\angle ZYX\)

 

We can use the pythagorean theorem to find \(XY\), because we know that \(XA = \frac{22}{2} = 11\) and \(AY = 14\). That will also be the length of \(WZ\)

So, what will the measures of the angles be? :D

 May 3, 2020

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