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I'm given the function. 

 

\(F(-2) =\)  

 

and I have the following point's on the graph (Since Webcalc's having a problem with uploading pictures) 

 

THE FOLLWOING POINTS: (1, -2), (0. 1), (-2, 2), (-3, 0); 

 

My answer for the question was 1 but I appread incorrect my judgement was based on how all my other problem's, when they would tell what x was and ask what F(x) was so I tried the opposite for this.

 

THANKS SO MUCH GUYS FOR YOUR HELP :)

 Jul 24, 2019
edited by HiylinLink  Jul 24, 2019
 #1
avatar+19787 
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I think you are given F (-2)    in the point  (-2,2)     i.e.   '2'

 Jul 24, 2019
 #2
avatar+429 
+1

Thank you, but I was curious how would one would derive the answer, as such?

HiylinLink  Jul 24, 2019
 #5
avatar+19787 
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Ya just have to 'derive' it from the information given and an understanding of what functions (f(x))= ....   mean unless you are actually GIVEN the function like (for example)   f(x) = x^2 +3x -1        

ElectricPavlov  Jul 24, 2019
 #7
avatar+429 
+1

Got it, that makes sense, Thanks for the time spent helping me!

HiylinLink  Jul 24, 2019
 #3
avatar+105462 
+4

F(-2)   actually asks..."When we put "-2" into "F".....what is the resulting y value???"

 

Look  at the points (x , y)....note that we have the point  (-2, 2)

 

This means that when we put -2  into F, we get get 2 as a result

 

So

 

F(-2)  =  2

 

 

cool cool cool

 Jul 24, 2019
 #4
avatar+429 
+2

OOOOOh so basically with the given point's it's asking if X or F('x') is equal to -2, we cehck our points to see which x is equal to negative 2 then check the Y value? 

 

 

Thanks for answering this quick!

HiylinLink  Jul 24, 2019
 #6
avatar+19787 
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Yeppers !

ElectricPavlov  Jul 24, 2019
 #8
avatar+429 
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I'm curious XD if I missed something extemly important, or I I'm correct XD

HiylinLink  Jul 24, 2019
 #9
avatar+105462 
+3

You didn't miss anything

 

F(x)  = y

So

F(-2)  =  y  ???

 

So    (x, y)  = (-2, y)    and the point with an x coordinate of -2   has a y coordinate of  2

 

So

f(-2)  = 2

 

 

cool cool cool

CPhill  Jul 24, 2019
 #10
avatar+429 
+1

Oh I see, THANKS!, really appricate this.

HiylinLink  Jul 24, 2019
 #11
avatar+792 
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travisio  Jul 24, 2019
 #12
avatar+429 
+1

Thanks, but it's outside of my acess aka my parental restrictions won't let me acess it.

HiylinLink  Jul 24, 2019
edited by HiylinLink  Jul 24, 2019
 #13
avatar+792 
+4

ohh dang dont worry im on school restriction but i have no parintal restriction because my parents don't know how and i aint tellin' them ethier

travisio  Jul 24, 2019
 #14
avatar+429 
+1

XD No it's fine, I don't have a proiblem with the restrictions, I get along pretty mcuh as every other kid does.

HiylinLink  Jul 24, 2019

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