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Rational Expressions 

Perform the indicated operations on rational expressions
(3/2y) + (5/3y^2)

 

(1/x-3) - (4/x-5)

 

(x^2-x-2/x-3) times (x^2-9/x+1)

 

(3/p + q/6) / (2q/3p)

Guest Aug 28, 2018
edited by Guest  Aug 28, 2018
 #1
avatar+7336 
+2

To make sure we understand your questions correctly, can you rewrite them to put parenthesees around each numerator and denominator?

For example.... to write the fraction  \(\frac{4a+1}{5b-2}\)  ,  you can write this:  (4a + 1)/(5b - 2)

 

The way it is currently written, this is your first expression:  \(\frac32y+\frac53y^2\)

But I think that might not be what you meant.

hectictar  Aug 28, 2018
 #2
avatar
+1

ok i did that

Guest Aug 28, 2018
 #3
avatar+7336 
+1

Okay, thanks for editing it! But just to make sure.....

 

(3/2y) + (5/3y^2)   means   \((\frac32y)+(\frac53y^2)\)

 

(1/x-3) - (4/x-5)   means   \((\frac1x-3)-(\frac4x-5)\)

 

(x^2-x-2/x-3) times (x^2-9/x+1)   means   \((x^2-x-\frac2x-3)(x^2-\frac9x+1)\)

 

(3/p + q/6) / (2q/3p)   means   \(\frac{\frac3p+\frac{q}6}{2\frac{q}3p}\)

 

....Are these what you meant?

hectictar  Aug 28, 2018
 #4
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+1

no thats not what i mean

Guest Aug 28, 2018
 #5
avatar+7336 
+1

To make your fractions what you mean, you need to put parenthesees around each numerator and denominator.

 

Every fraction should be in this format:  ( stuff in numerator )/(  stuff in denominator  )

 

For example,     \(\frac{x^2-x-2}{x-3}\)    must be written with parenthesees like this:     (x^2 - x - 2)/(x - 3)

 

I can probably guess what your fractions are supposed to be, but since I already started making a point about this.....I don't want to just give it up.   smiley

hectictar  Aug 28, 2018

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