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# hey guys i have a few questions that i will put in the text can yall explain them too i just dont understand at all

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Rational Expressions

Perform the indicated operations on rational expressions
(3/2y) + (5/3y^2)

(1/x-3) - (4/x-5)

(x^2-x-2/x-3) times (x^2-9/x+1)

(3/p + q/6) / (2q/3p)

Aug 28, 2018
edited by Guest  Aug 28, 2018

#1
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To make sure we understand your questions correctly, can you rewrite them to put parenthesees around each numerator and denominator?

For example.... to write the fraction  $$\frac{4a+1}{5b-2}$$  ,  you can write this:  (4a + 1)/(5b - 2)

The way it is currently written, this is your first expression:  $$\frac32y+\frac53y^2$$

But I think that might not be what you meant.

Aug 28, 2018
#2
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ok i did that

Guest Aug 28, 2018
#3
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Okay, thanks for editing it! But just to make sure.....

(3/2y) + (5/3y^2)   means   $$(\frac32y)+(\frac53y^2)$$

(1/x-3) - (4/x-5)   means   $$(\frac1x-3)-(\frac4x-5)$$

(x^2-x-2/x-3) times (x^2-9/x+1)   means   $$(x^2-x-\frac2x-3)(x^2-\frac9x+1)$$

(3/p + q/6) / (2q/3p)   means   $$\frac{\frac3p+\frac{q}6}{2\frac{q}3p}$$

....Are these what you meant?

Aug 28, 2018
#4
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no thats not what i mean

Guest Aug 28, 2018
#5
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To make your fractions what you mean, you need to put parenthesees around each numerator and denominator.

Every fraction should be in this format:  ( stuff in numerator )/(  stuff in denominator  )

For example,     $$\frac{x^2-x-2}{x-3}$$    must be written with parenthesees like this:     (x^2 - x - 2)/(x - 3)

I can probably guess what your fractions are supposed to be, but since I already started making a point about this.....I don't want to just give it up.

hectictar  Aug 28, 2018