We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

Rational Expressions

Perform the indicated operations on rational expressions

(3/2y) + (5/3y^2)

(1/x-3) - (4/x-5)

(x^2-x-2/x-3) times (x^2-9/x+1)

(3/p + q/6) / (2q/3p)

Guest Aug 28, 2018

edited by
Guest
Aug 28, 2018

#1**+2 **

To make sure we understand your questions correctly, can you rewrite them to put parenthesees around each numerator and denominator?

For example.... to write the fraction \(\frac{4a+1}{5b-2}\) , you can write this: (4a + 1)/(5b - 2)

The way it is currently written, this is your first expression: \(\frac32y+\frac53y^2\)

But I think that might not be what you meant.

hectictar Aug 28, 2018

#3**+1 **

Okay, thanks for editing it! But just to make sure.....

(3/2y) + (5/3y^2) means \((\frac32y)+(\frac53y^2)\)

(1/x-3) - (4/x-5) means \((\frac1x-3)-(\frac4x-5)\)

(x^2-x-2/x-3) times (x^2-9/x+1) means \((x^2-x-\frac2x-3)(x^2-\frac9x+1)\)

(3/p + q/6) / (2q/3p) means \(\frac{\frac3p+\frac{q}6}{2\frac{q}3p}\)

....Are these what you meant?

hectictar Aug 28, 2018

#5**+1 **

To make your fractions what you mean, you need to put parenthesees around each numerator and denominator.

Every fraction should be in this format: ( stuff in numerator )/( stuff in denominator )

For example, \(\frac{x^2-x-2}{x-3}\) must be written with parenthesees like this: (x^2 - x - 2)/(x - 3)

I can probably guess what your fractions are supposed to be, but since I already started making a point about this.....I don't want to just give it up.

hectictar
Aug 28, 2018