Rational Expressions

Perform the indicated operations on rational expressions

(3/2y) + (5/3y^2)

(1/x-3) - (4/x-5)

(x^2-x-2/x-3) times (x^2-9/x+1)

(3/p + q/6) / (2q/3p)

Guest Aug 28, 2018

edited by
Guest
Aug 28, 2018

#1**+2 **

To make sure we understand your questions correctly, can you rewrite them to put parenthesees around each numerator and denominator?

For example.... to write the fraction \(\frac{4a+1}{5b-2}\) , you can write this: (4a + 1)/(5b - 2)

The way it is currently written, this is your first expression: \(\frac32y+\frac53y^2\)

But I think that might not be what you meant.

hectictar Aug 28, 2018

#3**+1 **

Okay, thanks for editing it! But just to make sure.....

(3/2y) + (5/3y^2) means \((\frac32y)+(\frac53y^2)\)

(1/x-3) - (4/x-5) means \((\frac1x-3)-(\frac4x-5)\)

(x^2-x-2/x-3) times (x^2-9/x+1) means \((x^2-x-\frac2x-3)(x^2-\frac9x+1)\)

(3/p + q/6) / (2q/3p) means \(\frac{\frac3p+\frac{q}6}{2\frac{q}3p}\)

....Are these what you meant?

hectictar Aug 28, 2018

#5**+1 **

To make your fractions what you mean, you need to put parenthesees around each numerator and denominator.

Every fraction should be in this format: ( stuff in numerator )/( stuff in denominator )

For example, \(\frac{x^2-x-2}{x-3}\) must be written with parenthesees like this: (x^2 - x - 2)/(x - 3)

I can probably guess what your fractions are supposed to be, but since I already started making a point about this.....I don't want to just give it up.

hectictar
Aug 28, 2018