Hey i need your help, if sin(x)=opp/hyp... Than how can i find the hyp?

I assume you just want to "solve" for the hypoteneuse

So...

sin(x) = opp / hyp     ...  multiply both sides by hyp....this gives

hyp * sin(x) = opp    ...  now, divide both sides by sin(x)....we have

hyp = opp / sin(x)

Do Pythagorean thereom a^2+ b^2 = c^2 basically just multiply the tangent and ajacent sides to get the hypothenuse oppisite/adjacent

Wait chris how can he multiply both sides by the hypothenuse if he dosent know what the hypothenuse is? It says how can i find the hypothenuse....

We don't know what any of the actual "numbers" are, zegroes....this just gives a general procedure to get the hypoteneuse by itself on one side of the identity.

It's like asking you how the find the area of a square...we don't know the actual numbers, but we can give the answer that ..... A = s^2

Does that make sense??

I know i guess.i was just feeling sour because i worked hard on that answer. I kept going back to correct it to make sure it was perfect then to find out it was wrong.Yeah that sucked