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In acute triangle LMN, what is the measure of angle L to the nearest tenth of a degree? (Enter only the number.)

 Oct 9, 2014

Best Answer 

 #3
avatar+129852 
+5

We can use the Law of Cosines

17^2 = 11^2 + 14^2 - 2(11)(14)cos(L)

289 = 121 + 196 - 308cos(L)

-28 = -308cos(L)        divide both sides by -308

(28/308) = cos(L)        take the cosine invese

cos-1 (28/308) = about 84.8°

 

 Oct 9, 2014
 #1
avatar+472 
0

You dived 11,17,14 or you can muxtiyply 11, 17 then what you get for

that with the 14 then dived, what you got for 11,17 then 14 and what you got

from 11,17. 

 Oct 9, 2014
 #2
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0

I'm sorry, I can't understand what you are saying.

 Oct 9, 2014
 #3
avatar+129852 
+5
Best Answer

We can use the Law of Cosines

17^2 = 11^2 + 14^2 - 2(11)(14)cos(L)

289 = 121 + 196 - 308cos(L)

-28 = -308cos(L)        divide both sides by -308

(28/308) = cos(L)        take the cosine invese

cos-1 (28/308) = about 84.8°

 

CPhill Oct 9, 2014
 #4
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0

Thank you, guys! :)

 Oct 9, 2014

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