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The lines 3y + 2x =7 and y = mx - 11 are perpendicular. Find m

 

Please help :D 

 Nov 11, 2018
 #1
avatar+70 
+1

Sorry last confusing question im sorry!!!!

 

Write the equation y = 4/5x - 7/10  in standard form. (Standard form is Ax + By = C where A is positive, and A, B, and C are integers with greatest common divisor 1.)

 Nov 11, 2018
 #2
avatar+98107 
+1

In the form  Ax + By = C, the slope of the line is  -A / B

 

So....rearranging the given line as

 

2x + 3y  = 7......the slope is =  -A / B  =    -2 / 3

 

So....a perpendicular line will have  a negative reciprocal slope =   3 / 2  =  m

 

 

cool cool cool

 Nov 11, 2018
 #3
avatar+98107 
+1

For your other question, we have

 

y = (4/5)x - 7/10       we want to get rid of the fractions....so...multiply through by 10

 

10y  = 8x - 7       add 7 to both sides

 

7 + 10y  =  8x   subtract 0y from both sides

 

7 =  8x  - 10y       rearrange as

 

8x - 10y  =  7

 

 

cool cool cool

 Nov 11, 2018

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