The lines 3y + 2x =7 and y = mx - 11 are perpendicular. Find m
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Sorry last confusing question im sorry!!!!
Write the equation y = 4/5x - 7/10 in standard form. (Standard form is Ax + By = C where A is positive, and A, B, and C are integers with greatest common divisor 1.)
In the form Ax + By = C, the slope of the line is -A / B
So....rearranging the given line as
2x + 3y = 7......the slope is = -A / B = -2 / 3
So....a perpendicular line will have a negative reciprocal slope = 3 / 2 = m