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For what real values of $k$ does the quadratic $12x^2 + kx + 27 = 0$ have nonreal roots? Enter your answer as an interval.

 Mar 10, 2020

Best Answer 

 #1
avatar+21827 
+2

If discriminant is <0 then nonreal roots

 

b^2 - 4ac <0

k^2 -4(12)(27) <0

k^2 < 1296

K < 36  or >-36      (-36,36)

 Mar 10, 2020
 #1
avatar+21827 
+2
Best Answer

If discriminant is <0 then nonreal roots

 

b^2 - 4ac <0

k^2 -4(12)(27) <0

k^2 < 1296

K < 36  or >-36      (-36,36)

ElectricPavlov Mar 10, 2020

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