Hi! Could someone please help me with these??
determine whether the planes are parallel, orthogonal or neither
2x - y - 3z = -5
-2x - 6y - z = -3
5x - 2y - 4z = 6
-15x + 6y + 12z = -16
2x - y - 3z = -5
-2x - 6y - z = -3
A vector that is normal to the first plane is < -2, -1, -3 >
A vector that is normal to the second plane is <-2, -6, -1 >
The vectors are not proportional, thus the planes are not parallel
If the dot product of these two vectors = 0, then they are orthogonal
The dot product =
-2 * -2 + -1 * -6 + -3 * -1 = 4 + 6 + 3 = 13
Thus.......the planes are not orthogonal
Thus, these planes are neither parallel, nor orthogonal
5x - 2y - 4z = 6
-15x + 6y + 12z = -16
The normal vectors are < 5, -2, -4 > and <-15, 6, 12>
The vectors ars proportional because 3 times the first equals the second....thus.......these planes are parallel