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Hi! Could someone please help me with these??

 

 

determine whether the planes are parallel, orthogonal or neither

2x - y - 3z = -5

-2x - 6y - z = -3

 

 

 

 

5x - 2y - 4z = 6

-15x + 6y + 12z = -16

 Sep 2, 2016
 #1
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2x - y - 3z = -5

-2x - 6y - z = -3

 

A vector that is normal to the first plane is < -2, -1, -3 >

A vector that is normal to the second plane is <-2, -6, -1 >

 

The vectors are not proportional, thus the planes are not parallel

 

If the dot product of these two vectors = 0, then they are orthogonal

 

The dot product =

 

 -2 * -2  + -1 * -6 + -3 * -1   =   4 + 6 + 3  = 13

 

Thus.......the planes are not orthogonal

 

Thus, these planes are neither parallel, nor orthogonal

 

 

5x - 2y - 4z = 6

-15x + 6y + 12z = -16

 

The normal vectors are  < 5, -2, -4 >  and <-15, 6, 12>

 

The vectors ars proportional because 3 times the first equals the second....thus.......these planes are parallel

 

 

 

 

cool cool cool

 Sep 2, 2016

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